16x^2+36x-145=0

Solution for 16x^2+36x-145=0 equation:

16x^2+36x-145=0

a = 16; b = 36; c = -145;
Δ = b2-4ac
Δ = 362-4·16·(-145)
Δ = 10576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10576}=\sqrt{16*661}=\sqrt{16}*\sqrt{661}=4\sqrt{661}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{661}}{2*16}=\frac{-36-4\sqrt{661}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{661}}{2*16}=\frac{-36+4\sqrt{661}}{32}
$